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Note: Do you want to link to this page? Please link to: http://www.hobby-electronics.info/go.php?to=11102 The ability to transfer heat is called the thermal conductance, but we always use the reciprocal value: the heat resistance. The thermal resistance (Rth) is measured in °C/W. If the Rth of a heatsink is 1°C/W, the temperature will rise 1°C per Watt power dissipation. So: R=T/P Doesn't this folmula look familiar? Yep, if you replace T with V and P with I, you get the formula for electrical resistance. This anology makes it very easy to calculate the heak sink you need: replace all heat producers with current sources and temperatures with voltages. Take a look at the diagram below.
This diagram shows transistor T6 of the lab power supply, a 2N3055 producing 60W at its junction. (The junction is the silicon chip inside the transistor.) The thermal resistance from junction to case is 1.5°C/W. The ambient temperature is 25°C. Resistor RTHC-A is the thermal resistance of the heatsink. This is the resistance we want to calculate. The maximum junction temperature of the 2N3055 is 200°C. The 'temperature drop' across RTHJ-C is 60W∙1.5°C/W = 90°C. That leaves 200 - 90 - 25 = 85°C for the heatsink. So RTHC-A = 85°C/60W = 1.4°C/W. Let's now calculate the heatsink for T3, a TIP41A. The maximum junction temperature is 150°C. The datasheet says: when you keep the case temperature to 25°C, the transistor can dissipate 65W. This means that RTHJ-C = 125°C/65W = 1,9°C/W. The transistor dissipates 4.1W, so the total resistance from junction to ambient may not exceed 125°C/4.1W = 30.5°C/W. So the thermal resistance of the heatsink should not exceed 30.5 - 1.9 = 28.6°C/W. A very small heatsink will suffice. Important notes:
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